https://matte1b.mathonline.se/index.php?action=history&feed=atom&title=3.3_L%C3%B6sning_33.3 Lösning 3 - Versionshistorik2026-08-17T20:15:09ZVersionshistorik för denna sida på wikinMediaWiki 1.23.1https://matte1b.mathonline.se/index.php?title=3.3_L%C3%B6sning_3&diff=32668&oldid=prevTaifun: Skapade sidan med '::<math>\begin{array}{cccccrl} 2 & \cdot & (x\,+\,1) & = & 40 & \quad & {\rm Täck\;över\;} (x\,+\,1) \\ 2 & \cdot & \boxed{(x\,+\,1)}...'2017-07-10T13:59:50Z<p>Skapade sidan med '::<math>\begin{array}{cccccrl} 2 & \cdot & (x\,+\,1) & = & 40 & \quad & {\rm Täck\;över\;} (x\,+\,1) \\ 2 & \cdot & \boxed{(x\,+\,1)}...'</p>
<p><b>Ny sida</b></p><div>::<math>\begin{array}{cccccrl} 2 & \cdot & (x\,+\,1) & = & 40 & \quad & {\rm Täck\;över\;} (x\,+\,1) \\<br />
2 & \cdot & \boxed{(x\,+\,1)} & = & 40 & & \\<br />
2 & \cdot & \boxed{\quad\;\;?\quad\;\;} & = & 40 & & \\<br />
2 & \cdot & \boxed{\quad\;20\quad\;} & = & 40 & & <br />
\end{array}</math><br />
<br />
::::<math> \qquad \Downarrow </math><br />
<br />
::<math> \begin{array}{rclcl} (x\,+\,1) & = & 20 & & \\<br />
x\,+\,1 & = & 20 & \quad & {\rm Täck\;över\;} x \\<br />
\boxed{x}\,+\,1 & = & 20 & & \\<br />
\boxed{?}\,+\,1 & = & 20 & & \\<br />
\boxed{19}\,+\,1 & = & 20 & &<br />
\end{array}</math><br />
<br />
<math> \qquad \Downarrow </math><br />
<br />
<math> \;\;\; x \; = \; 19 </math></div>Taifun