Skillnad mellan versioner av "1.5 Lösning 9"
Från Mathonline
Taifun (Diskussion | bidrag) m |
Taifun (Diskussion | bidrag) m |
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| Rad 1: | Rad 1: | ||
| − | <math> \, ( | + | <math> \, (A + B) \, = \, 2\,^x \, + \, 2\,^{-x} \; + \; 2\,^x \, - \, 2\,^{-x} \, = \, 2\,^x \, + \, 2\,^x \; + \; 2\,^{-x} \, - \, 2\,^{-x} \, = \, 2 \cdot 2\,^x </math> |
| − | <math> \, ( | + | <math> \, (A - B) \, = \, 2\,^x \, + \, 2\,^{-x} \; - \; (2\,^x \, - \, 2\,^{-x}) \, = \, 2\,^x \, + \, 2\,^{-x} \; - \; 2\,^x \, + \, 2\,^{-x} \, = \, </math> |
<math> \qquad\qquad\; = \, 2\,^x \, - \, 2\,^x \; + \; 2\,^{-x} \, + \, 2\,^{-x} \, = \, 2 \cdot 2\,^{-x} </math> | <math> \qquad\qquad\; = \, 2\,^x \, - \, 2\,^x \; + \; 2\,^{-x} \, + \, 2\,^{-x} \, = \, 2 \cdot 2\,^{-x} </math> | ||
| − | <math> \, ( | + | <math> \, (A + B) \cdot (A - B) \, = \, 2 \cdot 2\,^x \, \cdot \, 2 \cdot 2\,^{-x} \, = \, 2 \cdot 2 \, \cdot \, 2\,^x \cdot 2\,^{-x} \, = \, 4 \, \cdot \, 2\,^{x\,-\,x} \, = \, </math> |
<math> \qquad\qquad\qquad\qquad\;\; = \, 4 \, \cdot \, 2\,^0 \, = \, 4 </math> | <math> \qquad\qquad\qquad\qquad\;\; = \, 4 \, \cdot \, 2\,^0 \, = \, 4 </math> | ||
Nuvarande version från 23 maj 2020 kl. 13.43
\( \, (A + B) \, = \, 2\,^x \, + \, 2\,^{-x} \; + \; 2\,^x \, - \, 2\,^{-x} \, = \, 2\,^x \, + \, 2\,^x \; + \; 2\,^{-x} \, - \, 2\,^{-x} \, = \, 2 \cdot 2\,^x \)
\( \, (A - B) \, = \, 2\,^x \, + \, 2\,^{-x} \; - \; (2\,^x \, - \, 2\,^{-x}) \, = \, 2\,^x \, + \, 2\,^{-x} \; - \; 2\,^x \, + \, 2\,^{-x} \, = \, \)
\( \qquad\qquad\; = \, 2\,^x \, - \, 2\,^x \; + \; 2\,^{-x} \, + \, 2\,^{-x} \, = \, 2 \cdot 2\,^{-x} \)
\( \, (A + B) \cdot (A - B) \, = \, 2 \cdot 2\,^x \, \cdot \, 2 \cdot 2\,^{-x} \, = \, 2 \cdot 2 \, \cdot \, 2\,^x \cdot 2\,^{-x} \, = \, 4 \, \cdot \, 2\,^{x\,-\,x} \, = \, \)
\( \qquad\qquad\qquad\qquad\;\; = \, 4 \, \cdot \, 2\,^0 \, = \, 4 \)
