Skillnad mellan versioner av "3.3 Lösning 1a"
Från Mathonline
Taifun (Diskussion | bidrag) m |
Taifun (Diskussion | bidrag) m |
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| Rad 2: | Rad 2: | ||
x \, + \, x \, + \, 6 & = & 12 & & \\ | x \, + \, x \, + \, 6 & = & 12 & & \\ | ||
2\,x \, + \, 6 & = & 12 & \qquad | & {\color{Red} {- \, 6}} \\ | 2\,x \, + \, 6 & = & 12 & \qquad | & {\color{Red} {- \, 6}} \\ | ||
| − | + | 2\,x \, + \, 6 \, {\color{Red} {- \, 6}} & = & 12 \, {\color{Red} {- \, 6}} & & \\ | |
2\,x \, & = & 6 & \qquad | & {\color{Red} {/ \; 2}} \\ | 2\,x \, & = & 6 & \qquad | & {\color{Red} {/ \; 2}} \\ | ||
\displaystyle \frac{2\,x}{{\color{Red} {2}}} & = & \displaystyle \frac{6}{{\color{Red} {2}}} & & \\ | \displaystyle \frac{2\,x}{{\color{Red} {2}}} & = & \displaystyle \frac{6}{{\color{Red} {2}}} & & \\ | ||
x \, & = & 3 & & | x \, & = & 3 & & | ||
\end{array}</math> | \end{array}</math> | ||
Versionen från 14 maj 2016 kl. 17.41
- \[\begin{array}{rclcl} x \, + \, (x \, + \, 6) & = & 12 & & \\ x \, + \, x \, + \, 6 & = & 12 & & \\ 2\,x \, + \, 6 & = & 12 & \qquad | & {\color{Red} {- \, 6}} \\ 2\,x \, + \, 6 \, {\color{Red} {- \, 6}} & = & 12 \, {\color{Red} {- \, 6}} & & \\ 2\,x \, & = & 6 & \qquad | & {\color{Red} {/ \; 2}} \\ \displaystyle \frac{2\,x}{{\color{Red} {2}}} & = & \displaystyle \frac{6}{{\color{Red} {2}}} & & \\ x \, & = & 3 & & \end{array}\]
