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Rad 1: |
| − | Vi sätter in <math> \, x = 3 \, </math> i ekvationen<span style="color:black">:</span> <math> \quad 16 \, + \, 2\,x \, = \, 14 </math>
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| − | VL <math> \, = \, 16 \, + \, 2 \cdot 3 \, = \, 16 \, + \, 6 \, = \, 22 </math>
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| − | HL <math> \, = \, 14 </math>
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| − | VL <math> \; \neq \; </math> HL <math> \quad \Longrightarrow \quad x = 3 \, </math> är ingen lösning.
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| − | Lösning<span style="color:black">:</span>
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| − | :<math>\begin{array}{rclcl} 16 \, + \, 2\,x & = & 14 & \qquad | & - \, 16 \\
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| − | 16 \, + \, 2\,x - \, 16 \, & = & 14 \, - \, 16 \, & & \\
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| − | 2\,x & = & -2 & \qquad | & / \, 2 \\
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| − | \displaystyle \frac{2\,x}{2} & = & \displaystyle \frac{-2}{2} & & \\
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| − | x & = & -1
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| − | \end{array}</math>
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