Skillnad mellan versioner av "3.3 Lösning 3b"
Från Mathonline
Taifun (Diskussion | bidrag) (Skapade sidan med '::<math>\begin{array}{rclcl} x \, + \, (x \, + \, 6) & = & 12 & & \\ x \, + \, x \, + \,...') |
Taifun (Diskussion | bidrag) m |
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Rad 7: | Rad 7: | ||
x \, & = & 3 & & | x \, & = & 3 & & | ||
\end{array}</math> | \end{array}</math> | ||
+ | |||
+ | Kontroll<span style="color:black">:</span> | ||
+ | |||
+ | <math> \, x = 3 \quad </math> insatt i <math> \quad x \, + \, (x \, + \, 6) \, = \, 12 \, </math><span style="color:black">:</span> | ||
+ | |||
+ | VL <math> \, = \, 3 \, + \, (3 \, + \, 6) \, = \, 3 \, + \, 3 \, + \, 6 \, = \, 12 </math> | ||
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+ | HL <math> \, = \, 12 </math> | ||
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+ | VL <math> \; = \; </math> HL <math> \quad \Longrightarrow \quad </math> OK |
Versionen från 16 maj 2016 kl. 14.09
- \[\begin{array}{rclcl} x \, + \, (x \, + \, 6) & = & 12 & & \\ x \, + \, x \, + \, 6 & = & 12 & & \\ 2\,x \, + \, 6 & = & 12 & \qquad | & - \, 6 \\ 2\,x \, + \, 6 \, - \, 6 & = & 12 \, - \, 6 & & \\ 2\,x \, & = & 6 & \qquad | & / \; 2 \\ \displaystyle \frac{2\,x}{2} & = & \displaystyle \frac{6}{2} & & \\ x \, & = & 3 & & \end{array}\]
Kontroll:
\( \, x = 3 \quad \) insatt i \( \quad x \, + \, (x \, + \, 6) \, = \, 12 \, \):
VL \( \, = \, 3 \, + \, (3 \, + \, 6) \, = \, 3 \, + \, 3 \, + \, 6 \, = \, 12 \)
HL \( \, = \, 12 \)
VL \( \; = \; \) HL \( \quad \Longrightarrow \quad \) OK